2018-07-04 09:06:45 +00:00
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# Copyright (C) 2001-2018, Python Software Foundation
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2018-07-04 09:08:42 +00:00
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# For licence information, see README file.
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2016-10-30 09:46:26 +00:00
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#
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msgid ""
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msgstr ""
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"Project-Id-Version: Python 3.6\n"
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"Report-Msgid-Bugs-To: \n"
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2017-04-02 20:14:06 +00:00
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"POT-Creation-Date: 2017-04-02 22:11+0200\n"
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2016-10-30 09:46:26 +00:00
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"PO-Revision-Date: YEAR-MO-DA HO:MI+ZONE\n"
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"Last-Translator: FULL NAME <EMAIL@ADDRESS>\n"
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2018-07-04 09:14:25 +00:00
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"Language-Team: FRENCH <traductions@lists.afpy.org>\n"
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2017-05-23 22:40:56 +00:00
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"Language: fr\n"
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2016-10-30 09:46:26 +00:00
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"MIME-Version: 1.0\n"
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"Content-Type: text/plain; charset=UTF-8\n"
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"Content-Transfer-Encoding: 8bit\n"
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#: ../Doc/library/codeop.rst:2
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msgid ":mod:`codeop` --- Compile Python code"
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msgstr ""
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#: ../Doc/library/codeop.rst:10
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msgid "**Source code:** :source:`Lib/codeop.py`"
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msgstr ""
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#: ../Doc/library/codeop.rst:14
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msgid ""
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"The :mod:`codeop` module provides utilities upon which the Python read-eval-"
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"print loop can be emulated, as is done in the :mod:`code` module. As a "
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"result, you probably don't want to use the module directly; if you want to "
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"include such a loop in your program you probably want to use the :mod:`code` "
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"module instead."
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msgstr ""
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#: ../Doc/library/codeop.rst:20
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msgid "There are two parts to this job:"
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msgstr ""
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#: ../Doc/library/codeop.rst:22
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msgid ""
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"Being able to tell if a line of input completes a Python statement: in "
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"short, telling whether to print '``>>>``' or '``...``' next."
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msgstr ""
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#: ../Doc/library/codeop.rst:25
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msgid ""
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"Remembering which future statements the user has entered, so subsequent "
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"input can be compiled with these in effect."
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msgstr ""
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#: ../Doc/library/codeop.rst:28
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msgid ""
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"The :mod:`codeop` module provides a way of doing each of these things, and a "
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"way of doing them both."
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msgstr ""
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#: ../Doc/library/codeop.rst:31
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msgid "To do just the former:"
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msgstr ""
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#: ../Doc/library/codeop.rst:35
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msgid ""
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"Tries to compile *source*, which should be a string of Python code and "
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"return a code object if *source* is valid Python code. In that case, the "
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"filename attribute of the code object will be *filename*, which defaults to "
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"``'<input>'``. Returns ``None`` if *source* is *not* valid Python code, but "
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"is a prefix of valid Python code."
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msgstr ""
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#: ../Doc/library/codeop.rst:41
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msgid ""
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"If there is a problem with *source*, an exception will be raised. :exc:"
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"`SyntaxError` is raised if there is invalid Python syntax, and :exc:"
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"`OverflowError` or :exc:`ValueError` if there is an invalid literal."
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msgstr ""
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#: ../Doc/library/codeop.rst:45
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msgid ""
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"The *symbol* argument determines whether *source* is compiled as a statement "
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"(``'single'``, the default) or as an :term:`expression` (``'eval'``). Any "
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"other value will cause :exc:`ValueError` to be raised."
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msgstr ""
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#: ../Doc/library/codeop.rst:51
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msgid ""
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"It is possible (but not likely) that the parser stops parsing with a "
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"successful outcome before reaching the end of the source; in this case, "
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"trailing symbols may be ignored instead of causing an error. For example, a "
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"backslash followed by two newlines may be followed by arbitrary garbage. "
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"This will be fixed once the API for the parser is better."
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msgstr ""
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#: ../Doc/library/codeop.rst:60
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msgid ""
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"Instances of this class have :meth:`__call__` methods identical in signature "
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"to the built-in function :func:`compile`, but with the difference that if "
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"the instance compiles program text containing a :mod:`__future__` statement, "
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"the instance 'remembers' and compiles all subsequent program texts with the "
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"statement in force."
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msgstr ""
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#: ../Doc/library/codeop.rst:69
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msgid ""
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"Instances of this class have :meth:`__call__` methods identical in signature "
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"to :func:`compile_command`; the difference is that if the instance compiles "
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"program text containing a ``__future__`` statement, the instance 'remembers' "
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"and compiles all subsequent program texts with the statement in force."
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msgstr ""
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